MCQ
Liquor poisoning is due to
- APresence of bad compound in liquor
- ✓Presence of methyl alcohol
- CPresence of ethyl alcohol
- DPresence of carbonic acid
✓
Answer
Correct option: B.
Presence of methyl alcohol
b
It’s Obvious.
It’s Obvious.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
When benzyl chloride is treated with ethanolic $KCN$, the major product formed is
→Given below are two statements :
→Statement $-I :$ The pentavalent oxide of group$- 15$ element. $E _{2} O _{5}$. is less acidic than trivalent oxide. $E _{2} O _{3}$. of the same element.
Statement $-II :$ The acidic character of trivalent oxide of group $15$ elements. $E _{2} O _{3}$. decreases down the group.
In light of the above statements. choose most appropriate answer from the options given below
Tertiary amines have lowest boiling points amongst isomeric amines because:
Which of the following is not correct reason for the substantially lower rate of reaction than the collision frequency?
${N_2}$ forms $NC{l_3}$, whereas $P$ can form both $PC{l_3}$ and $PC{l_5}$. Why
→Metals react differently with water. The more vigorous is the reaction, the more is the bubble formation. The following diagram illustrates the reaction of sodium, magnesium and copper with water.
What can be concluded from this diagram?
What can be concluded from this diagram?
In a galvanic cell, the salt bridge
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{PhMgBr{\text{ }} + {\text{ }}C{H_3}{\text{ }} - CN\xrightarrow[{{H_3}{O^ \oplus }}]{}(A)Ph - C - O - H\xrightarrow[{(2){H_3}O}]{{\left( 1 \right){\text{ }}excess{\text{ }}C{H_3}Li}}(A)}
→{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{PhMgBr{\text{ }} + {\text{ }}C{H_3}{\text{ }} - CN\xrightarrow[{{H_3}{O^ \oplus }}]{}(A)Ph - C - O - H\xrightarrow[{(2){H_3}O}]{{\left( 1 \right){\text{ }}excess{\text{ }}C{H_3}Li}}(A)}
\end{array}$
Same product $(A)$ will form in both reactions $A$ is
The equivalents of ethylene diamine required to replace the neutral ligands from the coordination sphere of the trans-complex of $CoCl _{3} \cdot 4 NH _{3}$ ............ is (Round off to the Nearest Integer).
→How many alcohols with molecular formula C4H10O are chiral in nature?