Local maximum and local minimum values of the function (x - 1) (x… - Vidyadip

MCQ

Local maximum and local minimum values of the function $(x - 1){(x + 2)^2}$ are

A
$-4, 0$
✓
$0, -4$
C
$4, 0$
D
None of these

✓

Answer

Correct option: B.

$0, -4$

b
(b) $f'(x) = 2(x - 1)(x + 2) + {(x + 2)^2} = 3{x^2} + 6x$

$f'(x) = 0$ ==>$x = 0,\, - 2$

$f( - 2) = ( - 2 - 1){( - 2 + 2)^2} = 0$ (Maximum value)

and $f(0) = (0 - 1){(0 + 2)^2} = - 4$ (Minimum value).

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