MCQ
The domain of function $\sin ^{-1} 2 x$ is :
  • A
    $[0,1]$
  • B
    $[-1,1]$
  • $\left[-\frac{1}{2}, \frac{1}{2}\right]$
  • D
    $[-2,2]$

Answer

Correct option: C.
$\left[-\frac{1}{2}, \frac{1}{2}\right]$
(C)
$\quad \sin ^{-1} 2 x$ will be defined if $-1 \leq 2 x \leq 1 \Rightarrow-\frac{1}{2} \leq$$
x \leq \frac{1}{2} \Rightarrow x \in\left[-\frac{1}{2}, \frac{1}{2}\right]
$
Hence correct option is (C)

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