where \({v_x} = v\cos \theta = \) Horizontal component of velocity
\({v_y} = v\sin \theta - gt = \) Vertical component of velocity
\({v_t} = \sqrt {{{(v\cos \theta )}^2} + {{(v\sin \theta - gt)}^2}} \)
\({v_t} = \sqrt {{v^2} + {g^2}{t^2} - 2v\sin \theta \,gt} \)
આપેલ : $1\, {ly}=9.46 \times 10^{15} \,{m},$ $\, {AU}=1.5 \times 10^{11}\, {m}$