Question
Magnetic field at the centre $O$ due to the given structure is



$B=B_{\text {due to circular arc }}+B_{\text {due to straight wires }}$
$=\frac{\mu_0 i}{2 R}\left(\frac{3 \pi}{2 \cdot(2 \pi)}\right)+\frac{\mu_0 i}{4 \pi R}$
$\Rightarrow B=\frac{\mu_0 i}{4 R}\left(\frac{3}{2}+\frac{1}{\pi}\right) \otimes$
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(Useful information) : $\sqrt{167 R T}=640 j^{1 / 2} mole ^{-1 / 2} ; \sqrt{140 RT }=590 j ^{1 / 2} mole ^{-1 / 2}$. The molar masses $M$ in grams are given in the options. Take the value of $\sqrt{\frac{10}{ M }}$ for each gas as given there.)



