
$B=B_{\text {due to circular arc }}+B_{\text {due to straight wires }}$
$=\frac{\mu_0 i}{2 R}\left(\frac{3 \pi}{2 \cdot(2 \pi)}\right)+\frac{\mu_0 i}{4 \pi R}$
$\Rightarrow B=\frac{\mu_0 i}{4 R}\left(\frac{3}{2}+\frac{1}{\pi}\right) \otimes$

(Neglect the effect of earth's magnetic field.)
