$ \Rightarrow \log E = \log \sigma + 4\log T$
$ \Rightarrow \log E = 4\log T + \log \sigma $
on comparing this equations with $y = mx + C$
we find that graph between log $E$ and log $T$ will be a straight line, having positive slope $(M=4)$ and intercept on log $E$ axis equal to $\log \sigma $


