MCQ
major product of this reaction is


- A

- ✓

- C

- D








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$STATEMENT-2$: The colour of the compound formed in the reaction of aniline with $\mathrm{NaNO}_2 / \mathrm{HCl}$ at $0^{\circ} \mathrm{C}$ followed by coupling with $\beta$-naphthol is due to the extended conjugation.
$[I]$ Only $A, B$ and $C$ react with $1\,M\,HCl$ to give $H_2\,(g)$
$[II]$ When $C$ is added to solutions of the other metal ions, metallic $B$ and $D$ are formed.
$[III]$ Metal $C$ does not reduce $A^{n+}$