Question
Making use of the cube root table, find the cube root 7342
✓
Answer
We have:
From cube root table, we have:
7300 < 7342 < 7400
$\Rightarrow\sqrt[3]{7000}<\sqrt[3]{7342}<\sqrt[3]{7400}$
From the cube root table, we have:
$\sqrt[3]{7300}=19.39 $ and $\sqrt[3]{7400}=19.48$
$\therefore$ For the difference of (7400 - 7300), i.e., 100, the difference in the values
= 19.48 - 19 - 39 = 0.09
$\therefore$ For the difference of (7342 - 7300), i.e., 42, the difference in the values
$=\frac{0.09}{100}\times42= 0.0378$
$= 0.037$
$\therefore\sqrt[3]{7342}$
$=19.39 +0.037$
$=19.427$
From cube root table, we have:
7300 < 7342 < 7400
$\Rightarrow\sqrt[3]{7000}<\sqrt[3]{7342}<\sqrt[3]{7400}$
From the cube root table, we have:
$\sqrt[3]{7300}=19.39 $ and $\sqrt[3]{7400}=19.48$
$\therefore$ For the difference of (7400 - 7300), i.e., 100, the difference in the values
= 19.48 - 19 - 39 = 0.09
$\therefore$ For the difference of (7342 - 7300), i.e., 42, the difference in the values
$=\frac{0.09}{100}\times42= 0.0378$
$= 0.037$
$\therefore\sqrt[3]{7342}$
$=19.39 +0.037$
$=19.427$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Referring the given figure of a parallelogram, write the answers of questions given below.
i. If l(WZ) = 4.5 cm, then l(XY) = ?
ii. If l(YZ) = 8.2 cm, then l(XW) = ?
iii. If l(OX) = 2.5 cm, then l(OZ) = ?
iv. If l(WO) = 3.3 cm, then l(WY) = ?
v. If m∠WZY = 120°, then m∠WXY = ? and m∠XWZ = ?
i. If l(WZ) = 4.5 cm, then l(XY) = ?
ii. If l(YZ) = 8.2 cm, then l(XW) = ?
iii. If l(OX) = 2.5 cm, then l(OZ) = ?
iv. If l(WO) = 3.3 cm, then l(WY) = ?
v. If m∠WZY = 120°, then m∠WXY = ? and m∠XWZ = ?
A die is thrown at random. Find the probability of getting:
- 2.
- A number less than 3.
- A composite number.
- A number not less than 4.
If we have 15 boys and 5 girls in a class which carries a higher probability? Getting a copy belonging to a boy or a girl. Can you give it a value?
Factorize :
44x² – x – 3
Evaluate $\left(-8 x^2 y^5\right) \times(-20 x y)$ for $x=2.5$ and $y=1$
→By what numbers should the following be divided to get a perfect square in case? Also, find the number whose square is the new number.
3698
3698
Evaluate $\left(2.3 a ^5 b^2\right) \times\left(1.2 a ^2 b^2\right)$ when $a =1$ and $b =0.5$.
→Plot the given points on a graph sheet and check if they lie on a straight line. If not, name the shape they form when joined in the given order.
J(4, 3), K(6, 1), L(6, 5) and M(4, 7)
J(4, 3), K(6, 1), L(6, 5) and M(4, 7)
Observe the following pattern,
$(1\times2)+(2\times3)=\frac{2\ \times\ 3\ \times\ 4}{3}$
$(1\times2)+(2\times3)+(3\times4)=\frac{3\ \times\ 4\ \times\ 5}{3}$
$(1\times2)+(2\times3)+(3\times4)+(4\times5)=\frac{4\ \times\ 5\ \times\ 6}{3}$
and find the value of,
$(1\times2)+(2\times3)+(3\times4)+(4\times5)$
→$(1\times2)+(2\times3)=\frac{2\ \times\ 3\ \times\ 4}{3}$
$(1\times2)+(2\times3)+(3\times4)=\frac{3\ \times\ 4\ \times\ 5}{3}$
$(1\times2)+(2\times3)+(3\times4)+(4\times5)=\frac{4\ \times\ 5\ \times\ 6}{3}$
and find the value of,
$(1\times2)+(2\times3)+(3\times4)+(4\times5)$
Mohan wants to buy a trapezium shaped field. Its side along the river is parallel and twice the side along the road. If the area of this field is $10500 m^2$ and the perpendicular distance between the two parallel sides is 100 m , find the length of the side along the river.
→