Question
Making use of the cube root table, find the cube root 7800

Answer

We have:
7800 = 78 × 100
$\therefore\sqrt[3]{7800}$
$=\sqrt[3]{78\times100}$
$=\sqrt[3]{78}\times\sqrt[3]{100}$
By the cube root table, we have:
$=\sqrt[3]{78}=4.273$ and $\sqrt[3]{100}=4.642$
$\therefore\sqrt[3]{7800}$
$=\sqrt[3]{78}\times\sqrt[3]{100}$
$=4.273\times4.642$
$=19.835$ (Up to three decimal places)
Thus, the answer is 19.835.

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