MCQ
Manganese $(VI)$ has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is $...... .$
  • $3$
  • B
    $2$
  • C
    $1$
  • D
    $4$

Answer

Correct option: A.
$3$
a
$MnO _{4}^{2-}$ disproportionates in a neutral or acidic solution to give $MnO _{4}^{-}$and $Mn ^{+4}$

$3 MnO _{4}^{2-}+3 H ^{+} \longrightarrow 2 MnO _{4}^{-}+ MnO _{2}+2 H _{2} O$

O.S. of $Mn$ in $MnO _{4}^{-}=+7$

O.S. of $Mn$ in $MnO _{2}=+4$

$\text { difference }=3$

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