Download App

Playing With Numbers — MATHS STD 6 — Question

Gujarat BoardEnglish MediumSTD 6MATHSPlaying With Numbers1 Mark
MCQ
Mark $(\checkmark)$ against the correct answer in the following:
The greatest number which divides $134$ and $167$ leaving $2$ as remainder in each case is:
  • A
    $14$
  • B
    $17$
  • C
    $19$
  • ✓
    $33$
✓

Answer

Correct option: D.
$33$

Since we need $2$ as the remainder, we will subtract $2$ from each of the numbers.
$167 - 2 = 165$
$134 - 2 = 132$
Now, any of the common factors of $165$ and $132$ will be the required divisor.
On factorising:
$165 = 3 \times 5 \times 11$
$132 = 2 \times 2 \times 3 \times 11$
Their common factors are $11$ and $3.$
So, $3 \times 11 = 33$ is the required divisor.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q. [1 Marks Each]" from Playing With Numbers→Playing With Numbers — all question types→MATHS STD 6 question papers→Gujarat Board STD 6 question papers→Gujarat Board question paper generator→

Similar questions

On subtracting -9 from -6 , we get
→
Find the perimeter of a square of length $25\ cm:$
→
→
If $bc : ac : ab = 1 : 2 : 3$ then find $\frac{\text{a}}{\text{bc}}:\frac{\text{b}}{\text{ca}}$
→
If $x < -1,$ then $x^2$
→
Mark the correct alternative of the following:If $\frac{1}{3}+\frac{1}{2}+\frac{1}{\text{x}}=4,$ then $x =$ ?
→
Let points $A, B$ and $C$ lies on a line. If $B$ lies between $A$ and $C, AC = 15\ cm$ and $BC = 9\ cm.$ What is $AB^2?$
→
The number of lines of symmetry of the letter O of the English alphabet is
→
Line has __________ fixed length:
→
Find the missing term in the given sequence. $4, 9, 29, ?, 599, 35994,9,29, ? ,599, 3599$
→