MCQ
Mark the correct alternative in the following: What least value should be given to $^*$ so that the number $6342^*1$ is divisible by $3$?
  • A
    $0$
  • B
    $1$
  • $2$
  • D
    $3$

Answer

Correct option: C.
$2$
Sum of the given digits $= 6 + 3 + 4 + 2 + 1 = 16$
We know that multiple of $3$ greater than $16$ is $18.$
$\therefore 18 - 16 = 2$
Therefore, the smallest required digit is $2.$

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