Question
Match each item given under the column $C_1$ to its correct answer given under the column $C_2.$
Five boys and five girls form a line. Find the number of ways of making the seating arrangement under the following condition:
 
$C_1$
  $C_2$
$(a)$
Boys and girls alternate.
$(i)$ $5! \times 6!$
$(b)$
No two girls sit together.
$(ii)$ $10! – 5! 6!$
$(c)$
All the girls sit together.
$(iii)$ $(5!)^2+ (5!)^2$
$(d)$
All the girls are never together.
$(iv)$ $2!\  5!\  5!$

Answer

 
$C_1$   $C_2$
$(a)$ Boys and girls alternate. $(iii)$ $(5!)^2+ (5!)^2$
$(b)$ No two girls sit together. $(i)$ $5! \times 6!$
$(c)$ All the girls sit together. $(iv)$ $2!\  5!\  5!$
$(d)$ All the girls are never together. $(ii)$ $10!\  5!\  6!$
Total number of arrangment when boys and girls alternate:$ = (5!)^2 + (5!)^2$
  1. No two girls sit together: $= 5!\  6!$
  2. All the girls sit never toghether $= 2!\  5!\  5!$
  3. All the girls sit never together $= 10!\  5!\  6!$

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