Question
Match the coordinates given in Column $A$ with the items mentioned in Column $B.$
 
Column $A$
 
Column $B$
$(1)$
$(0, 5)$
$(a)$
$y$ coordinate is $2 \times x - $coordinate $+\ 1$.
$(2)$
$(2, 3)$
$(b)$
Coordinates of origin.
$(3)$
$(4, 8)$
$(c)$
Only $y–$coordinate is zero.
$(4)$
$(3, 7)$
$(d)$
The distance from $x –$axis is $5$.
$(5)$
$(0, 0)$
$(e)$
$y$ coordinate is double of $x –$coordinate.
$(6)$
$(5, 0)$
$(f)$
The distance from $y–$axis is $2$.

Answer

 
Column A
 
Column B
$(1)$
$(0, 5)$
$(d)$
The distance from $x–$ axis is $5$.
$(2)$
$(2, 3)$
$(f)$
The distance from $y–$axis is $2$.
$(3)$
$(4, 8)$
$(e)$
$y$ coordinate is double of $x –$coordinate.
$(4)$
$(3, 7)$
$(a)$
$y$ coordinate is $2 \times x - $coordinate $+\ 1$.
$(5)$
$(0, 0)$
$(b)$
Coordinates of origin.
$(6)$
$(5, 0)$
$(c)$
Only $y–$coordinate is zero.
Solution:
$a.$ In the pair $(0, 5)$, the second number also known as ordinate represents the distance from $X-$axis, i.e. $5$.
$b.$ In the pair $(2, 3), 2$ the first number, also known as abscissa represents the distance from $Y-$axis that is $2$.
$c.$ We have the coordinates $(4, 8)$. Clearly, coordinate is double of $x-$coordinate.
$d.$ We have the coordinate $(3, 7)$, where $x-$coordinate $= 3$ and $y-$coordinate $= 7$
Evidently, $y-$coordinate $= 2 \times x-$coordinate $+\ 1$
$e. (0, 0)$ are the coordinates of origin.
$f.$ In the point $(5, 0)$, the $y-$coordinate is zero.

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