Question
Solve $0.35(4 x-2)=0.05(12 x+0.4)$
✓
Answer
We have, $0.35(4 x-2)=0.05(12 x+0.4)$
Let us open the bracket,
$ \begin{array}{l} \text { LHS }=0.35 \times 4 x-0.35 \times 2=1.4 x-0.7 \\ \text { RHS }=0.05 \times 12 x+0.05 \times 0.04=0.6 x+0.02 \end{array} $
Now, the equation is
$14 x-0.7=0.6 x+0.02 \Rightarrow 1.4 x-0.6 x=0.7+0.02\quad$
[transposing $0.6 x$ to LHS and -0.7 to RHS]
$\Rightarrow \quad 0.8 x=0.72 \Rightarrow x=\frac{0.72}{0.8}$
$\therefore \quad x=0.9$
Let us open the bracket,
$ \begin{array}{l} \text { LHS }=0.35 \times 4 x-0.35 \times 2=1.4 x-0.7 \\ \text { RHS }=0.05 \times 12 x+0.05 \times 0.04=0.6 x+0.02 \end{array} $
Now, the equation is
$14 x-0.7=0.6 x+0.02 \Rightarrow 1.4 x-0.6 x=0.7+0.02\quad$
[transposing $0.6 x$ to LHS and -0.7 to RHS]
$\Rightarrow \quad 0.8 x=0.72 \Rightarrow x=\frac{0.72}{0.8}$
$\therefore \quad x=0.9$
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