MCQ
$\mathop {\lim }\limits_{\theta \to 0} \frac{{\sin 3\theta - \sin \theta }}{{\sin \theta }} = $
- A$1$
- ✓$2$
- C$1/3$
- D$3/2$
Aliter : $\mathop {\lim }\limits_{\theta \to 0} \,\frac{{\sin 3\theta - \sin \theta }}{{\sin \theta }} $
$= \mathop {\lim }\limits_{\theta \to 0} \,\frac{{\sin 3\theta }}{{\sin \theta }} - \mathop {\lim }\limits_{\theta \to 0} \,\frac{{\sin \theta }}{{\sin \theta }}$
$ = \frac{3}{1} - 1 = 2.$
You may also apply $L-$ Hospital rule.
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