MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{1 - \cos 2x}}{x} = $
  • $0$
  • B
    $1$
  • C
    $2$
  • D
    $4$

Answer

Correct option: A.
$0$
a
(a)$\mathop {\lim }\limits_{x \to 0} \,\,\frac{{x\,.\,2\,{{\sin }^2}x}}{{{x^2}}} = 2.\mathop {\lim }\limits_{x \to 0} {\left( {\frac{{\sin x}}{x}} \right)^2} \cdot \mathop {\lim }\limits_{x \to 0} x = 0$.

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