12. limits — ગણિત ધોરણ 11 સાયન્સ — Question

$ = \mathop {\lim }\limits_{x \to 0} \,\left[ {{{\left\{ {\frac{{\sin {\textstyle{{mx} \over 2}}}}{{{\textstyle{{mx} \over 2}}}}} \right\}}^2}\,\,\,\frac{{{m^2}{x^2}}}{4}.\frac{1}{{{{\left\{ {\frac{{\sin {\textstyle{{nx} \over 2}}}}{{{\textstyle{{nx} \over 2}}}}} \right\}}^2}}}.\frac{4}{{{n^2}{x^2}}}} \right]$

$ = \frac{{{m^2}}}{{{n^2}}} \times 1 = \frac{{{m^2}}}{{{n^2}}}$.

Aliter : Apply $L$-Hospital’s rule,

$\mathop {\lim }\limits_{x \to 0} \frac{{1 - \cos mx}}{{1 - \cos nx}} = \mathop {\lim }\limits_{x \to 0} \frac{{m\sin mx}}{{n\sin nx}} $

$= \mathop {\lim }\limits_{x \to 0} \frac{{{m^2}\cos mx}}{{{n^2}\cos nx}} = \frac{{{m^2}}}{{{n^2}}}.$