MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{5\sin x + x\cos x}}{{2\tan x - {x^2}}}$ =
- A$\frac{5}{2}$
- ✓$3$
- C$0$
- Dઅસ્તિતવ નથી
$\mathop {\lim }\limits_{x \to 0} \frac{{5\frac{{\sin x}}{x} + \cos x}}{{\frac{{2\tan x}}{x} - x}} = \frac{{5 + 1}}{{2 - 0}} = 3$
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