MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{\cos (\sin x) - 1}}{{{x^2}}} = $
- A$1$
- B$-1$
- C$1/2$
- ✓$-1/2$
$= \mathop {{\rm{lim}}}\limits_{x \to 0} \frac{{ - 2{{\sin }^2}\left( {\frac{{\sin x}}{2}} \right)}}{{{x^2}}} = - 2.\frac{1}{4} = \frac{{ - 1}}{2}$.
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