MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{{e^{\frac{1}{x}}}}}{{{e^{\left( {\frac{1}{x} + 1} \right)}}}} = $
- A$0$
- B$1$
- CDoes not exist
- ✓None of these
$ = \mathop {{\rm{lim}}}\limits_{x \to 0} \frac{1}{e} = {e^{ - 1}}$.
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