MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{\sqrt {1 - \cos {x^2}} }}{{1 - \cos x}} = . . .$
- A$\frac{1}{2}$
- B$2$
- ✓$\sqrt 2 $
- Dએકપણ નહી.
$ = \frac{1}{{\sqrt 2 }}\,\mathop {\lim }\limits_{x \to 0} \,\left( {\frac{{\frac{{\sin \,({x^2}/2)}}{{{x^2}/2}}}}{{{{\left( {\frac{{\sin \,(x/2)}}{{x/2}}} \right)}^2}}}} \right).\frac{{{x^2}/2}}{{{x^2}/4}} = \sqrt 2 $.
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