MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{{x^3}\cot x}}{{1 - \cos x}} = $
- A$0$
- B$1$
- ✓$2$
- D$-2$
$ = \mathop {\lim }\limits_{x \to 0} \,{\left( {\frac{x}{{\sin x}}} \right)^3} \times \mathop {\lim }\limits_{x \to 0} \,\cos x \times \mathop {\lim }\limits_{x \to 0} \,(1 + \cos x) = 2$
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$(A)$ $Z \cup T_1 \cup T_2 \subset S$
$(B)$ $T_1 \cap\left(0, \frac{1}{2024}\right)=\phi$, where $\phi$ denotes the empty set
$(C)$ $T_2 \cap(2024, \infty) \neq \phi$
$(D)$ For any given $a, b \in Z , \cos (\pi(a+b \sqrt{2}))+i \sin (\pi(a+b \sqrt{2})) \in Z$ if and only if $b=0$, where $i=\sqrt{-1}$