MCQ
$\mathop {\lim }\limits_{x \to 0} {\left( {\frac{{1 + \tan x}}{{1 + \sin x}}} \right)^{{\rm{cosec }}x}} = . . .$
- A$e$
- B$\frac{1}{e}$
- ✓$1$
- Dએકપણ નહી.
$ = \mathop {\lim }\limits_{x \to 0} \,{[{\{ 1 + \tan x)^{\cot \,x}}\} ^{sec\,x}} \times \{ 1/{(1 + \sin x)^{\cos ec\,x}}\} ]$
$ = {e^{\sec \,\,0}}.\frac{1}{e} = e\,.\,\frac{1}{e} = 1.$
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