_ x 1 x^3 - 1 x^2 + 5x - 6 = - Vidyadip

MCQ

$\mathop {\lim }\limits_{x \to 1} \frac{{{x^3} - 1}}{{{x^2} + 5x - 6}} = $

A
$0$
✓
$\frac{3}{7}$
C
$\frac{1}{2}$
D
$ - \frac{1}{6}$

✓

Answer

Correct option: B.

$\frac{3}{7}$

b
(b) $\mathop {\lim }\limits_{x \to 1} \,\frac{{(x - 1)\,\,({x^2} + x + 1)}}{{(x - 1)\,\,(x + 6)}} = \frac{3}{7}$.

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