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STD 11 - 12. limits — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsSTD 11 - 12. limits1 Mark
MCQ
$\mathop {\lim }\limits_{x \to 3} \left\{ {\frac{{x - 3}}{{\sqrt {x - 2} - \sqrt {4 - x} }}} \right\} = $
  • ✓
    $1$
  • B
    $2$
  • C
    $-1$
  • D
    $-2$
✓

Answer

Correct option: A.
$1$
a
(a) $\mathop {\lim }\limits_{x \to 3} \,\left\{ {\frac{{x - 3}}{{\sqrt {x - 2} - \sqrt {4 - x} }}} \right\} = \mathop {\lim }\limits_{x \to 3} \,\frac{{(x - 3)\,\left\{ {\sqrt {x - 2} + \sqrt {4 - x} } \right\}}}{{2\,(x - 3)}} = 1$.

Aliter : Apply  $ L-$ Hospital’s rule.

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