Question
$\mathop {\lim }\limits_{x \to \alpha } \frac{{\sin x - \sin \alpha }}{{x - \alpha }} = $
$\mathop {\lim }\limits_{x \to \alpha } \,\,\frac{{\cos x}}{1} = \cos \alpha $, ($L$- हॉस्पीटल नियम से)
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$2 x+3 y-z=-2$
$x+y+z=4$
$x-y+|\lambda| z=4 \lambda-4$
जहाँ $\lambda \in R$, का कोई हल ना हो, तब