MCQ
$\mathop {\lim }\limits_{x \to - \infty } \frac{{\sqrt {4{x^2} + 5x + 8} }}{{4x + 5}} = . . .$
- ✓$ - 1/2$
- B$0$
- C$1/2$
- D$1$
$ = \mathop {\lim }\limits_{h \to 0} \,\,\frac{{\sqrt {4\,{{( - 1/h)}^2} + 5\,( - 1/h) + 8} }}{{4\,( - 1/h) + 5}}$
$ = \mathop {\lim }\limits_{h \to 0} \,\,\frac{{(1/h)\sqrt {4\, - 5h + 8{h^2}} }}{{(1/h)\,( - \,4 + 5h)}} = \frac{{\sqrt 4 }}{{ - 4}} = - \frac{1}{2}$.
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