MCQ
$\mathop {\lim }\limits_{x \to \pi /4} \frac{{{{\cot }^3}\,x - \tan \,x}}{{\cos \left( {x + \pi /4} \right)}}$ =
- A$4$
- B$4 \sqrt 2$
- C$8 \sqrt 2$
- D$8$
$\mathop {\lim }\limits_{x \to \frac{\pi }{4}} \frac{{3{{\cot }^2}x\left( { - \cos \,e{c^2}x} \right) - {{\sec }^2}x}}{{ - \sin \left( {x + \frac{\pi }{4}} \right)}} = 8$
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