MCQ
$\mathop {Limit}\limits_{x\,\, \to \,\,4} $ $\frac{{{{(\cos \,\alpha )}^x}\, - \,\,{{(\sin \,\alpha )}^x}\, - \,\,\cos \,2\alpha }}{{x\,\, - \,\,4}}=$
where $0 < \alpha <$ $\frac{\pi }{2}$
- A$cos^4\, \alpha\, ln \,cos\, \alpha\,+ \,sin^4\, \alpha\, ln sin\, \alpha$
- B$-\,cos^4\, \alpha\, ln \,cos\, \alpha - sin^4\, \alpha\, ln sin\, \alpha$
- C$-\,cos^4\, \alpha\, ln \,cos\, \alpha - \,sin^4\, \alpha\, ln sin\, \alpha$
- ✓$cos^4\, \alpha\, ln \,cos\, \alpha - sin^4\, \alpha\, ln sin\, \alpha$