( 2 + ) ( 2 - ) = - Vidyadip

MCQ

$\tan \theta \sin \left( {\frac{\pi }{2} + \theta } \right)\cos \left( {\frac{\pi }{2} - \theta } \right) = $

A
$1$
B
$0$
C
$\frac{1}{{\sqrt 2 }}$
✓
None of these

✓

Answer

Correct option: D.

None of these

d
(d) $\tan \theta \cos \theta \sin \theta = {\sin ^2}\theta $.

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