STD 12 - 5. Co-ordination chemistry — JEE STD 11 Science — Question

$Ni ( CO )_4 \Rightarrow 28+4 \times 2=36$

$(i)$ $V ( CO )_6 \Rightarrow 23+2 \times 6=35$

$(ii)$ $Cr ( CO )_5 \Rightarrow 24+2 \times 5=34$

$(iii)$ $Cu ( CO )_3 \Rightarrow 29+2 \times 3=35$

$(iv)$ $Mn ( CO )_5 \Rightarrow 25+2 \times 5=35$

$(v)$ $Fe ( CO )_5 \Rightarrow 26+2 \times 5=36$

$(vi)$ $\left[ Co ( CO )_3\right]^{3-} \Rightarrow 27+3+2 \times 3=36$

$(vii)$ $\left[ Cr ( CO )_4\right]^{4-} \Rightarrow 24+4+2 \times 4=36$

$(viii)$ $\left[\operatorname{Ir}( CO )_3\right] \Rightarrow 77+2 \times 3=83$