MCQ
Mean $–$ Mode $=$
- A$3($Mean $–$ Mode$)$
- B$3($Median $–$ Mean$)$
- ✓$3($Mean $–$ Median$)$
- D$3($Mode $–$ Mean$)$
✓
Answer
Correct option: C.
$3($Mean $–$ Median$)$
Since, Mean $– $ Mode $+$ Mean $+ \ 2$ Mode $= 3$ Median
$\Rightarrow $ Mean $–$ Mode $= 3$ Median $–$ Mean $– 2$ Mode
$= 3$ Median $–$ Mean $– 2 \ (3$ Median $–\ 2$ Mean$)$
$= 3$ Median $–$ Mean $– 6$ Median $+ \ 4$ Mean
$= 3$ Mean $– 3$ Median
$= 3($Mean $–$ Median$)$
$\Rightarrow $ Mean $–$ Mode $= 3$ Median $–$ Mean $– 2$ Mode
$= 3$ Median $–$ Mean $– 2 \ (3$ Median $–\ 2$ Mean$)$
$= 3$ Median $–$ Mean $– 6$ Median $+ \ 4$ Mean
$= 3$ Mean $– 3$ Median
$= 3($Mean $–$ Median$)$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If one root of the equation $a x^2+b x+c=0$ is three times the other, then
→The total surface area of a hemisphere of radius $7\ cm$ is:
→If $-\frac{1}{2}$ is a root of the equation $x^2-k x-\frac{5}{4}=0$, then the value of $k$ is
→Two coins are tossed together. The probability of getting at most one head is :
The quadratic equation $ax^2+ 2x + a = 0$ has two distinct roots, if :
→The next term of the A.P. $\sqrt{7}, \sqrt{28}, \sqrt{63}, \ldots$
→In the given circle, $O$ is a centre and $\angle B D C=42^{\circ}$, then $\angle A C B$ is equal to
→Find the area of shaded portion, where the length of it is $14$ units and radius of the upper semicircle is $7$ units :
A
→AIn triangles ABC and DEF, $\angle\text{A}=\angle\text{E}=40^\circ,$ AB : ED = AC : EF and $\angle\text{F}=65^\circ,$ then $\angle\text{B}=$
→$3 . \overline{27}$ is
→