hence, $ x+1(0)+2(-2)=1$
$\therefore ,$ $x=3$
Coming on to Coordination Number
Both en and $\mathrm{C}_2O_4$ are didentate ligand
$\therefore $ $C . N =2(2)+1(2) =6$
adding eq $(1)$ and $(2)$ we get
$6+3$ $=9$
$(I)\,[Cr(NO_3)_3(NH_3)_3]$ $(II)\, K_3[Fe(C_2O_4)_3]$ $(III)\,[CoCl_2(en)_2]^+$ $(IV)\, [CoBrCl(ox)_2]^{3-}$
$(I)\, [Ma_3b_2c]^{n \pm}\,\,\, (II)\, [M(AB)_3]^{n \pm}\,\,\, (III)\, [Ma_2b_2c_2]^{n \pm}$
$(I)\,\,\,-\,\,\,(II)\,\,\,-\,\,\,(III)$
$(1)\ [CO(NH_3)_5(NO_2)]Cl$ અને $[CO(NH_3)_5(ONO)]Cl_2$ લીન્કેજ
$(2)\ [Cu(NH_3)_4][PtCl_4]$ અને $[Pt(NH_3)_4][CuCl_4]$ સવર્ગ
$(3)\ [Pt(NH_3)_4Cl_2]Br_2$ અને $[Pt(NH_3)_4Br_2)]Cl_2$ આયનીકરણ