$ \Rightarrow 2.71\;eV = 2.5\;eV + \frac{1}{2} \times 9.1 \times {10^{ - 31}} \times v_{\max }^2$
$ \Rightarrow 0.21 \times 1.6 \times {10^{ - 19}} = \frac{1}{2} \times 9.1 \times {10^{ - 31}} \times v_{\max }^2$
$ \Rightarrow {v_{\max }} = 2.65 \times {10^5}\;m/s$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List$-I$ | List$-II$ |
| $(a)$ Torque | $(i)$ ${MLT}^{-1}$ |
| $(b)$ Impulse | $(ii)$ ${MT}^{-2}$ |
| $(c)$ Tension | $(iii)$ ${ML}^{2} {T}^{-2}$ |
| $(d)$ Surface Tension | $(iv)$ ${MI} {T}^{-2}$ |
Choose the most appropriate answer from the option given below :