Methyl alcohol on oxidation with acidified K_2 C r_2 O_7 gives

$\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}$ $\xrightarrow[{{\text{H}}_{2}}{{\text{O}}_{2}},\bar{O}\text{H}]{\text{B}{{\text{H}}_{3}},\text{THF}}(P)$ $\xrightarrow[\text{C}{{\text{H}}_{2}}\text{C}{{\text{l}}_{2}}]{\text{ Pyridinium Chloro Chromate }(\text{PCC})}$ $(Q)$

$\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}$ $\xrightarrow[NaB{{H}_{4}}\,,\,H{{O}^{\Theta }}]{Hg\,{{(OAc)}_{2}}\,,\,{{H}_{2}}O}(R)$ $\xrightarrow[\text{C}{{\text{H}}_{2}}\text{C}{{\text{l}}_{2}}]{\text{ Pyridinium Chloro Chromate }(\text{PCC})}$ $(S)$

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In infinite dilutions, the equivalent conductances of $B{a^{2 + }}$ and $C{l^ - }$ are $127$ and $76$ $oh{m^{ - 1}}c{m^{ - 1}}$ $eqv{t^{ - 1}}$. The equivalent conductivity of $BaC{l_2}$at indefinite dilution is

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Metals are usually used as catalysts belong to:

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$C{H_3} - CH = CH - CH(OH) - C{H_3}\mathop {\xrightarrow{{{\text{Jon's}}}}}\limits_{{\text{reagent}}} $ $X$,

Product $ X$ is

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Coloured salts are formed by

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Which shows optical isomerism ?

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