MCQ
Methyl cyanide on reaction with sodium and $\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}$ forms:
- ✓Ethyl amine
- BEthanoic acid
- CEthanimine
- DNone of these
✓
Answer
Correct option: A.
Ethyl amine
Methyl cyanide on reaction with sodium and ethanol forms ethylamine.
$\text{CH}_3-\text{C}\equiv\text{N}+4[\text{H}]\xrightarrow{\text{Na}/\text{ethanol}}\text{CH}_3-\text{CH}_2-\text{NH}_2$
In this reaction, the nitrile group is hydrogenated to form a primary amine.
This is a useful method to increase the length of a carbon chain in preparing a primary amine which contains one more carbon atom than the alkyl halide from which alkyl cyanide is obtained.
$\text{CH}_3-\text{C}\equiv\text{N}+4[\text{H}]\xrightarrow{\text{Na}/\text{ethanol}}\text{CH}_3-\text{CH}_2-\text{NH}_2$
In this reaction, the nitrile group is hydrogenated to form a primary amine.
This is a useful method to increase the length of a carbon chain in preparing a primary amine which contains one more carbon atom than the alkyl halide from which alkyl cyanide is obtained.
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