Question
Methylamine reacts with $\ce{HNO_2}$ to form $......... .$

Answer

$\text{R}-\text{NH}_2+\text{HNO}_2\xrightarrow{\ \ \ \ \text{NaNO}_2+\text{HCI}\ \ \ }[\text{R}-\stackrel{+}{\hbox{N}}_2\text{C}\stackrel{-}{\hbox{l}}]\xrightarrow{\ \ \text{H}_2\text{O}\ \ }\text{ROH}+\text{N}_2+\text{HCl}$

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