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Amines Chemistry - Amines

Rajasthan Board (RBSE) - STD 12 Science - Chemistry (Rajasthan - English Medium). 408 questions in this chapter.

Question types

Amines question types

408 questions across 8 question groups — pick any mix to generate a Chemistry paper with step-by-step answer keys.

408
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8
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5
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Sample Questions

Amines questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 6Assertion (A) & Reason (B) MCQ1 Mark
In these questions, a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
  1. Assertion and reason both are correct statements and reason is correct explanation for assertion.
  2. Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  3. Assertion is correct statement but reason is wrong statement.
  4. Assertion is wrong statement but reason is correct statement.
Assertion: Boiling point of amines are lower than those of alcohols and carboxylic acids.
Reason: Amines are much more soluble in water than less polar solvents like alcohol, ether, etc.
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Q 7Assertion (A) & Reason (B) MCQ1 Mark
Note: In the following question a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
  1. Both assertion and reason are wrong.
  2. Both assertion and reason are correct statements but reason is not correct explanation of assertion.
  3. Assertion is correct statement but reason is wrong statement.
  4. Both assertion and reason are correct statements and reason is correct explanation of assertion.
  5. Assertion is wrong statement but reason is correct statement.
Assertion: Acylation of amines gives a monosubstituted product whereas alkylation of amines gives polysubstituted product.
Reason: Acyl group sterically hinders the approach of further acyl groups.
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Q 8Assertion (A) & Reason (B) MCQ1 Mark
In these questions, $a$ statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion: Aniline hydrogen sulphate, on heating, forms $p-$ aminosulphonic acid.
Reason: The sulphonic acid group is electron$-$withdrawing.
  • A
    Assertion and reason both are correct statements and reason is correct explanation for assertion.
  • ✓
    Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  • C
    Assertion is correct statement but reason is wrong statement.
  • D
    Assertion is wrong statement but reason is correct statement.

Answer: B.

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Q 9Assertion (A) & Reason (B) MCQ1 Mark
In these questions, a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
  1. Assertion and reason both are correct statements and reason is correct explanation for assertion.
  2. Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  3. Assertion is correct statement but reason is wrong statement.
  4. Assertion is wrong statement but reason is correct statement.
Assertion: Nitration of aniline can be done conveniently by protecting the amino group by acetylation.
Reason: Acetylation increases the electron density in the benzene ring.
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Q 10Assertion (A) & Reason (B) MCQ1 Mark
In these questions, a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
  1. Assertion and reason both are correct statements and reason is correct explanation for assertion.
  2. Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  3. Assertion is correct statement but reason is wrong statement.
  4. Assertion is wrong statement but reason is correct statement.
Assertion: Ammonolysis of alkyl halides involves the reaction between alkyl halides and alcoholic ammonia.
Reason: Reaction can be used to prepare 1º, 2º, 3º amines and finally quaternary ammonium salts.
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Q 192 Marks Questions2 Marks
Give the structures of A, B and C in the following reaction:
$\text{C}_6\text{H}_5\text{NO}_2\xrightarrow[]{\text{Fe}/\text{HCl}}\text{A}\xrightarrow[273\text{K}]{\text{HNO}_2}\text{B}\xrightarrow[]{\text{C}_6\text{H}_5\text{OH}}\text{C}$
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Q 202 Marks Questions2 Marks
Write structures of different isomers corresponding to the molecular formula, $\ce{C_3H_9N}.$ Write $\ce{IUPAC}$ names of the isomers which will liberate nitrogen gas on treatment with nitrous acid.
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Q 213 Marks Question3 Marks
Give reasons for the following$:$
  1. Acetylation of aniline reduces its activation effect.
  2. $\ce{CH_3NH_2}$ is more basic than $\ce{C_6H_5NH_2}.$
  3. Although $-\ce{NH_2}$ is $o/p$ directing group, yet aniline on nitration gives a significant amount of $m-$nitroaniline.
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Q 223 Marks Question3 Marks
Give reasons for the following $:$
  1. Acetylation of aniline reduces its activation effect.
  2. $\ce{CH_3NH_2}$ is more basic than $\ce{C_6H_5NH_2}.$
  3. Although $-\ce{NH2}$ is $o/p$ directing group, yet aniline on nitration gives a significant amount of $m-$nitroaniline.
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Q 233 Marks Question3 Marks
Give reasons for the following:
  1. Aniline does not undergo Friedal$-$Crafts reaction.
  2. $(CH_3)_2 NH$ is more basic than $(CH_3)_3 N$ in an aqueous solution.
  3. Primary amines have higher boiling point than tertiary amines.
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Q 243 Marks Question3 Marks
Give reasons for the following:
  1. Acetylation of aniline reduces its activation effect.
  2. $\ce{CH_3NH_2}$ is more basic than $\ce{C_6H_5NH_2}.$
  3. Although $-\ce{NH_2}$ is $o/p$ directing group, yet aniline on nitration gives a significant amount of $m-$nitroaniline.
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Q 26Case study (4 Marks)4 Marks
Read the passage given below and answer the following questions: Amines are produced when an alcoholic solution of ammonia and an alkyl or a benzyl halide is heated in a sealed tube at 373K. This reaction is called ammonolysis and usually gives a mixture of primary, secondary and tertiary amines along with some quarternary ammonium salts. This reaction is an example of nucleophilic substitution reaction in which ammonia acts as a nucleophile due to the presence of a lone pair of electrons on the nitrogen atom. However this method cannot be used for the preparation of aryl amines. One of the most convenient methods for the preparation of aryl amines is reduction of nitro compounds. Aryl amines can also be prepared by reduction of nitrites or Gabriel phthalimide synthesis. A statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
  1. Assertion and reason both are correct statements and reason is correct explanation for assertion.
  2. Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  3. Assertion is correct statement but reason is wrong statement.
  4. Assertion is wrong statement but reason is correct statement.
  1. Assertion: Ammonolysis of alkyl halides only produces 2° amines.
Reason: Ammonolysis of alkyl halides involves the reaction between alkyl halides and alcoholic ammonia.
  1. Assertion: Gabriel-phthalimide reaction can be used to prepare both aryl and alkyl primary amines.
Reason: Aryl halides are more reactive alkyl halides towards nucleophilic substitution reactions.
  1. Assertion: Anunonolysis method cannot be used for the preparation of aryl amines.
Reason: Aryl halides are much less reactive than alkyl halides towards nucleophilic substitution reaction.
  1. Assertion: Ammonolysis can be used to prepare pure primary amines.
Reason: Ammonolysis of haloalkanes lead to multiple ammonium salts.
  1. Assertion: Aromatic 1º amines can not be prepared by Gabriel phthalimide synthesis.
Reason: Aryl halides do not undergo nucleophilic substitution with anion formed by phthalimide.
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Q 27Case study (4 Marks)4 Marks
Read the passage given below and answer the following questions:
Amines are alkyl or aryl derivatives of ammonia formed by replacement of one or more hydrogen atoms. Alkyl derivatives are called aliphatic amines and aryl derivatives are known as aromatic amines. The presence of aromatic amines can be identified by performing dye test. Aniline is the simplest example of aromatic amine. It undergoeselectrophilic substitution reactions in which $-\ce{NH_2}$ group strongly activates the aromatic ring through delocalisation of lone pair of electrons of $N-$atom. Aniline undergoes electrophilic substitution reactions. Ortho and para positions to the $-\ce{NH_2}$ group become centres of high electrons density. Thus, $-\ce{NH_2}$ group is ortho and para$-$directing and powerful activating group.
The following questions are multiple choice questions. Choose the most appropriate answer:
  1. Cyclohexylamine and aniline can be distinguished by:
  1. Hinsberg test.
  2. carbylamine test.
  3. Lassaigne test.
  4. azo dye test.
  1. Which of the following compounds gives dye test?
  1. Aniline.
  2. Methyl amine.
  3. Diphenyl amine.
  4. Ethyl amine.
  1. Aniline when acetylated, the major product on nitration followed by alkaline hydrolysis gives:
  1.  Acetanilide.
  2. $o-$nitroacetanitide.
  3. $p-$nitroaniline.
  4. $m-$nitroanitine.
  1. Oxidation of aniline with manganese dioxide and sulphuric acid produces:
  1. Phenylhydroxylamine.
  2. Nitrobenzene.
  3. $p-$benzoquinone.
  4. Phenol.
  1. Aniline when treated with cone. $\ce{HNO_3}$ and $\ce{H_2SO_4}$​​​​​​​​​​​​​​ gives:
  1.  $p-$phenylenediamine.
  2. $m-$nitroaniline.
  3. $p-$benzoquinone.
  4. Nitrobenzene.
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Q 28Case study (4 Marks)4 Marks
Read the passage given below and answer the following questions:
The amines are basic in nature due to the presence of a lone pair of electron on $N-$atom of the $-NH_2$ group, which it can donate to electron deficient compounds. Aliphatic amines are stronger bases than $NH_3$ because of the $+I$ effect of the alkyl groups. Greater the number of alkyl groups attached to $N-$atom, higher is the electron density on it and more will be the basicity. Thus, the order of basic nature of amines is expected to be $3^\circ > 2^\circ > 1^\circ ,$ however the observed order is $2^\circ > 1^\circ > 3^\circ .$ This is explained on the basis of crowding on $N-$atom of the amine by alkyl groups which hinders the approach and bonding by a proton, consequently, the electron pair which is present on $N$ is unavailable for donation and hence $3^\circ$ amines are the weakest bases.
Aromatic amines are weaker bases than ammonia and aliphatic amines. Electron-donating groups such as $-\ce{CH_3, -OCH_3,}$ etc. increase the basicity while electron-withdrawing substitutes such as $\ce{-NO_2, -CN,}$ halogens, etc. decrease the basicity of amines. The effect of these substituents is more at $p$ than at $m-$positions.
The following questions are multiple choice questions. Choose the most appropriate answer:
  1. Which one of the following is the strongest base in aqueous solution?
  1. Methyl amine.
  2. Tri methyl amine.
  3. Aniline.
  4. Dimethyl amine.
  1. Which order ofbasicity is correct?
  1. Aniline $>$ $m-$toluidine $> o-$toluidine
  2. Aniline $> o-$toluidine $> m-$toluidine
  3. $o-$toluidine $>$ aniline $> m-$toluidine
  4. $o-$toluidine $<$ aniline $< m-$toluidine
  1. What is the decreasing order of basicity of primary, secondary and tertiary ethylamines and $NH_3$?
  1. $\ce{NH_3 > C_2H_5NH_2 > (C_2H_5)_2NH > (C_2H_5)_3N}$
  2. $\ce{(C_2H_5)_3N > (C_2H_5)_2NH_{ }> C_2H_5NH_2 > NH_3}$
  3. $\ce{(C_2H_5)_2NH > C_2H_5NH_2> (C_2H_5)_3N > NH_3}$
  4. $\ce{(C_2H_5)_2NH > (C_2H_5)_3N > C_2H_5NH_2 > NH_3​​​​​​​}$
  1. The order of basic strength among the following amines in benzene solution is:
  1. $\ce{CH_3NH_2 > (CH_3)_3N > (CH_3)_2NH}$
  2. $\ce{(CH_3)_3N > (CH_3)_2NH > CH_3NH_2​​​​​​​}$
  3. $\ce {CH_3NH_2 > (CH_3)_2NH > (CH_3)_3N}$
  4. $\ce{(CH_3)_3N > CH_3NH_2 > (CH_3)_2NH}$
  1. Choose the correct statement.
  1. Methylamine is slightly acidic.
  2. Methylamine is less basic than ammonia.
  3. Methylamine is a stronger base than ammonia.
  4. Methylamine forms salts with alkalies.
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Q 29Case study (4 Marks)4 Marks
Read the passage given below and answer the following questions: Aniline activates the benzene ring by increasing electron density at ortho$-$and para$-$positions. Hence, it is $o-, p-$directing. $-NH-2$ group strongly activates the ring therefore it is difficult to stop the reaction at monosubstitution stage. Among electrophilic substitution reaction, direct nitration of aniline is not done to get $o-$ and $p-$nitroaniline because lone pair of electrons present at nitrogen atom will accept proton from nitrating mixture to give anilinium ion which is meta$-$directing. Aniline with $NaNO_2$ and $\text{HCI}$ forms benzene diazonium chloride at very low temperature. Aromatic amines react with nitrous acid to form a yellow oily liquid known as $N-$nitrosoamines. A statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
  1. Assertion and reason both are correct statements and reason is correct explanation for assertion.
  2. Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  3. Assertion is correct statement but reason is wrong statement.
  4. Assertion is wrong statement but reason is correct statement.
  1. Assertion: Nitrating mixture used for carrying out nitration of benzene consists of cone. $HNO_3 +$ cone. $H_2SO_4.$
Reason: In presence of $\ce{H_2SO_4, HNO_3}$ acts as a base and produces $\text{NO}^+_2$ ions.
  1. Assertion: Anilinium chloride is more acidic than ammonium chloride.
Reason: Anilinium ion is not resonance$-$stabilised.
  1. Assertion: Nitrobenzene can be prepared from benzene by using mixture of cone. $HNO_3$ and cone. $H_2SO_4.$
Reason: In the mixture, $H_2SO_4$ act as a acid.
  1. Assertion: In strongly acidic solution, aniline becomes less reactive towards electrophilic reagents.
Reason: The amino group being completely protonated in strongly acidic solution, the lone pair of electrons on the nitrogen is no longer available for resonance.
  1. Assertion: Nitration of aniline can be done conveniently by protecting $-NH_2$ group through acetylation.
Reason: Acetylation of aniline results in the increase of electron density in the benzene ring.
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Q 30Case study (4 Marks)4 Marks
Read the passage given below and answer the following questions:
A mixture of two aromatic compounds $(A)$ and $(B)$ was separated by dissolving in chloroform followed by extraction with aqueous $\ce{KOH}$ solution. The organic layer containing compound $(A),$ when heated with alcoholic solution of $\ce{KOH}$ produce $\ce{C_7H_5N (C)}$ associated with unpleasant odour.
The following questions are multiple choice questions. Choose the most appropriate answer:
  1. What is $A?$
  1. $\ce{C_6H_5NH_2}$
  2. $\ce{C_6H_5CH_3}$
  3. $\ce{C_6H_5CH_3}$
  4. None of these.
  1. The reaction of $(A)$ with alcoholic solution of $\ce{KOH}$ to produce $(C)$ of unpleasant odour is called:
  1. Sandmeyer reaction.
  2. Carbylamine reaction.
  3. Ullmann reaction.
  4. Reimer$-$Tiemann reaction..
  1. The alkaline aqueous layer $(B)$ when heated with chloroform and then acidified give a mixture of isomeric compounds of molecular formula $\ce{C_7H_6O_2. (B)}$ is:
  1. $\ce{C_6H_5CHO}$
  2. $\ce{C_6H_5COOH}$
  3. $\ce{C_6H_5CH_3}$
  4. $\ce{C_6H_5OH}$
  1. In the chemical reaction,
  2. $\ce{CH_3CH_2NH_2 + CHCl_3 + 3KOH \rightarrow (A)+ (B) + 3H_2O,}$
  1. $\ce{C_2H_5NC}$ and $\ce{KCl}$
  2. $\ce{C_2H_5CN}$ and $\ce{KCl}$
  3. $\ce{CH_3CH_2CONH_2}$ and $\ce{KCl}$
  4. $\ce{C_2H_5NC}$ and $\ce{K_2CO_3}$
  1. Direct nitration of an aromatic compound $(A)$ is not feasible because:
  1. The reaction cannot be stopped at the mononitration stage.
  2. A mixture of $o, m$ and $p-$nitroaniline is always obtained.
  3. Nitric acid oxidises most of the aromatic compound to give oxidation products along with only a small amount of nitrated products.
  4. All of the above.
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Q 315 Marks Questions5 Marks
A colourless substance $'A\ ' (C_6H_7N)$ is sparingly soluble in water and gives a water soluble compound $'B\ '$ on treating with mineral acid. On reacting with $CHCl_3$ and alcoholic potash $'A\ '$ produces an obnoxious smell due to the formation of compound $'C\ '$. Reaction of $'A\ '$ with benzenesulphonyl chloride gives compound $'D\ '$ which is soluble in alkali. With $NaNO_2$ and $\text{HCl,} 'A\ '$ forms compound $'E\ '$ which reacts with phenol in alkaline medium to give an orange dye $'F\ '.$ Identify compounds $'A\ '$ to $'F\ '.$
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Q 325 Marks Questions5 Marks
A hydrocarbon $‘A\ ’, (C_4H_8)$ on reaction with $\text{HCl}$ gives a compound $‘B\ ’, (C_4H_9Cl),$ which on reaction with $1$ mol of $NH_3$ gives compound $‘C\ ’, (C_4H_{11}N).$ On reacting with $NaNO_2$ and $\text{HCl}$ followed by treatment with water, compound $‘C\ ’$ ields an optically active alcohol,$ ‘D\ ’.$ Ozonolysis of $‘A\ ’$ gives $2$ moles of acetaldehyde. Identify the compounds $‘A\ ’$ to $‘D\ ’. $Explain the reactions involved.
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Q 335 Marks Questions5 Marks
Answer the following questions:
How will you bring about the following conversions?
  1. Ethanamine into methanamine.
  2. Aniline into 1, 3, 5-tribromobenzene.
  3. Aniline into 4-bromoaniline.
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Q 345 Marks Questions5 Marks
A hydrocarbon $'A', (C_4H_8)$ on reaction with $HCl$ gives a compound $'B', (C_4H_9Cl)$, which on reaction with $1 \ mol$ of $NH_3$ gives compound $'C', (C_4H_{11}N)$. On reacting with $NaNO_2$ and $HCl$ followed by treatment with water, compound $'C\ '$ yields an optically active alcohol,$'D\ '$. Ozonolysis of $'A\ '$ gives $2$ mols of acetaldehyde. Identify compounds $'A\ '$ to $'D\ '$. Explain the reactions involved.
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Q 355 Marks Questions5 Marks
$\text{[A], [B], [C], [D], [E], [F]}$ and $[G]$ are amines each of which forms a hydrochloride containing $32.42\%$ chlorine. $\text{[A], [B], [C]}$ and $[D]$ evolve $N_2$ on reaction with $HNO_2$, but $\text{[E], [F], [G]}$ and $[H]$ do not. Give structures of $[A]$ to $[H]$ with reasons.
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