MCQ
Methylamine reacts with $H\ce{NO_2}$ to form $........$
- A$\ce{CH_3-O-N=O}$
- B$\ce{CH_3-O-CH_3}$
- ✓$\ce{CH_3OH}$
- D$\ce{CH_3CHO}$
✓
Answer
Correct option: C.
$\ce{CH_3OH}$
$\text{R}-\text{NH}_2+\text{HNO}_2\xrightarrow{\ \ \ \ \text{NaNO}_2+\text{HCI}\ \ \ }[\text{R}-\stackrel{+}{\hbox{N}}_2\text{C}\stackrel{-}{\hbox{l}}]\xrightarrow{\ \ \text{H}_2\text{O}\ \ }\text{ROH}+\text{N}_2+\text{HCl}$
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