MCQ
$\mid\text{a}\times\text{b}\mid^2+\mid\text{a.b}\mid^2=144$ and $\mid\text{a}\mid=4$ then $\mid\text{b}\mid$ is equal to:
  • A
    $12$
  • $3$
  • C
    $8$
  • D
    $4$

Answer

Correct option: B.
$3$

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