MCQ
Minimum excitation potential of Bohr's first orbit in hydrogen atom is.....$V$
- A$13.6$
- B$3.4 $
- ✓$10.2$
- D$3.6$
✓
Answer
Correct option: C.
$10.2$
c
(c) Excitation potential$ = \frac{{{\rm{Excitation \,\,energy}}}}{{\rm{e}}}$
(c) Excitation potential$ = \frac{{{\rm{Excitation \,\,energy}}}}{{\rm{e}}}$
Minimum excitation energy corresponds to excitation from $n = 1$ to $n = 2$
Minimum excitation energy in hydrogen atom $ = - 3.4 - ( - 13.6) = + 10.2\,eV$
so minimum excitation potential $= 10.2\, eV.$
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