A current of $3$ $amp$ is flowing in a plane circular coil of radius $4\, cm$ and number of turns $20$. The coil is placed in a uniform magnetic field of magnetic induction $0.5\, tesla$. Then, the dipole moment of the coil is.....$A-m^2$
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Magnetic moment $\mathrm{M}$ is given by:
$ \mathrm{M} =\mathrm{NIA}$
$=20 \times 3 \times \pi \times(4 / 100)^{2} $
$=0.3 \mathrm{\,amp} \times \mathrm{metre}^{2} $
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