Question
$M{L^3}{T^{ - 1}}{Q^{ - 2}}$ is dimension of
✓
Answer
(a) Resistivity $[\rho ] = \frac{{[R]\,.\,[A]}}{{[l]}}$
${\rm{where }} [R] = [M{L^2}{T^{ - 1}}{Q^{ - 2}}]$
$\therefore $ $[\rho ] = [M{L^3}{T^{ - 1}}{Q^{ - 2}}]$
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