Maharashtra BoardEnglish MediumSTD 9ScienceMeasurement of Matter3 Marks
Question
Molecular formula $-A1Cl_3$
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Answer
$\text { Molecular mass of } AlCl_3(M)$
$=(\text { Atomic mass of } Al) \times 1+(\text { Atomic mass of } Cl) \times 3$
$=(27 \times 1)+(35.5 \times 3)$
$=27+106.5$
$=133.5$
$\therefore \text { Molecular mass of } A1C1_3(M)=133.5$
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