Monochromatic radiation of wavelength is incident on a hydrogen s… - Vidyadip

MCQ

Monochromatic radiation of wavelength $\lambda$ is incident on a hydrogen sample containing in ground state. Hydrogen atoms absorb the light and subsequently emit radiations of ten different wavelengths. The value of $\lambda$ is.....$nm$

✓
$95 $
B
$103$
C
$73$
D
$88$

✓

Answer

Correct option: A.

$95 $

a
$\frac{n(n-1)}{2}=10$

$\rightarrow n=5$

$\frac{1}{\lambda}=R\left[1-\frac{1}{5^{2}}\right]$

$\Rightarrow \frac{1}{\lambda}=R\left[\frac{25-1}{25}\right]$

$\Rightarrow=\frac{25}{24 \times 109677} \mathrm{cm}$

$\Rightarrow \lambda=95 n m$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 12. atoms→12. atoms — all question types→Physics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

Let $n _{ p }$ and $n _{ e }$ be the number of holes and conduction electrons respectively in a semiconductor. Then

If the atom $_{100}F{m^{257}}$ follows the Bohr model and the radius of $_{100}F{m^{257}}$ is $n$ times the Bohr radius, then find $n$

The weight of an empty balloon on a spring balance is $W_1$. The weight becomes $W_2$ when the balloon is filled with air. Let the weight of the Air itself be $\omega$ neglect the thickness of the balloon when it is filled with air. Also neglect the difference in the densities of air inside and outside the balloon.

A wire when connected to $220\,V$ mains supply has power dissipation ${P_1}$. Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is ${P_2}$. Then ${P_2}:{P_1}$ is

The radioactivity of a certain radioactive element drops to 1/64 of its initial value in 30 seconds. Its half life is

Maxwell’s equations describe the fundamental laws of

The magnetic needle of a tangent galvanometer is deflected at an angle $30^o$ due to a magnet. The horizontal component of earth’s magnetic field $0.34 \times {10^{ - 4}}\,T$ is along the plane of the coil. The magnetic intensity is

Potential difference across the $40\,\Omega $ resistance will be ............ $V$

The isotope ${ }_5^{12} \mathrm{~B}$ having a mass $12.014 \mathrm{u}$ undergoes $\beta$-decay to ${ }_6^{12} \mathrm{C} .{ }_6^{12 .}$ has an excited state of the nucleus $\left({ }_6^{12} \mathrm{C}^*\right)$ at $4.041 \mathrm{MeV}$ above its ground state. If ${ }_5^{12} \mathrm{~F}$ decays to ${ }_6^{12} \mathrm{C}^*$, the maximum kinetic energy of the $\beta$-particle in units of $\mathrm{MeV}$ is ( $1 \mathrm{u}=931.5 \mathrm{MeV} / c^2$, where $c$ is the speed of light in vacuum).

the given potentiometer has its wire of resistance $10\, \Omega$. When the sliding contact is in the middle of the potentiometer wire, the potential drop across $2\, \Omega$ resistor is -