Question
Moon is seen to be of $\Big(\frac{1}{2}\Big)^\circ$ diameter from the earth. What must be the relative size compared to the earth?
✓
Answer
According to the problem, moon is seen as $\Big(\frac{1}{2}\Big)^\circ$ diameter from earth and earth is seen as $2^\circ$ diameter from moon.
As $\theta$ is proportional to diameter,
Hence, $\frac{\text{Diameter of earth}}{\text{Diameter of moon}}=\frac{2}{\Big(\frac{1}{2}\Big)}=4$
As $\theta$ is proportional to diameter,
Hence, $\frac{\text{Diameter of earth}}{\text{Diameter of moon}}=\frac{2}{\Big(\frac{1}{2}\Big)}=4$
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