MCQ
Most stable carbonium ion is
- A${\mathop C\limits^ + _2}{H_5}$
- B${(C{H_3})_3}\mathop C\limits^ + $
- ✓${({C_6}{H_5})_3}\mathop C\limits^ + $
- D${C_6}{H_5}\mathop C\limits^ + {H_2}$
✓
Answer
Correct option: C.
${({C_6}{H_5})_3}\mathop C\limits^ + $
c
(c)In the triphenyl methyl carbonium ion the $\pi$ electrons of all the three benzene rings are delocalised with the vacant $p-$orbital of central carbon atom. So, it is resonance stabilised. It is the most stable of all the carbonium ions given
(c)In the triphenyl methyl carbonium ion the $\pi$ electrons of all the three benzene rings are delocalised with the vacant $p-$orbital of central carbon atom. So, it is resonance stabilised. It is the most stable of all the carbonium ions given
The ion $C{H_3} - \mathop {\mathop {{C^ + }}\limits_{|\;\;}^{|\;\;} \;\;}\limits_{C{H_3}}^{C{H_3}} $ is stabilised by hyperconjugation, a second order resonance.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In ethane and cyclohexane which one of the following pairs of conformations are more stable
$NH_4CN$ is a salt of weak acid $HCN (K_a = 6.2 \times 10^{-10})$ and a weak base $NH_4OH (K_b = 1.8 \times 10^{-5})$. A one molar solution of $NH_4CN$ will be:
→The orbital having two radial as well as two angular nodes is
The first law of thermodynamics is only
If the mass table of atomic weights were established with oxygen atom assigned a value of $100,$ the atomic weight of carbon would be
→Acetylene is prepared by the action of water on:
The first and second ionisation enthalpies of a metal are $496$ and $4560 \;\mathrm{kJ} \mathrm{mol}^{-1},$ respectively. How many moles of $\mathrm{HCl}$ and $\mathrm{H}_{2} \mathrm{SO}_{4}$ respectively, will be needed to react completely with $1$ mole of the metal hydroxide?
→$(A)$ & $(B)$ are isomers. Product $(B)$ is :Dewar's Benzene
→The presence of ozone in the atmosphere of earth :
Which of the following product is not formed during this reaction
→$\,\begin{array}{*{20}{c}}
{\,C{H_3} - \,CH - \,CH = C{H_2}\,\xrightarrow{{B{r_2}/aq.NaCl}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$