MCQ
મુખ્ય કિંમત શોધો : $\tan ^{-1}(-1)$
- A$-\frac{\pi}{6}$
- B$\frac{\pi}{4}$
- C$-\frac{\pi}{2}$
- D$-\frac{\pi}{4}$
Then, $\tan y=-1=-\tan \left(\frac{\pi}{4}\right)=\tan \left(-\frac{\pi}{4}\right)$
We know that the range of the principal value branch of $\tan ^{-1}$ is $\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$ and $\tan \left(-\frac{\pi}{4}\right)=-1$
Therefore, the principal value of $\tan ^{-1}(-1)$ is $-\frac{\pi}{4}$
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તો $\left[ {\vec p \,\,\,\vec q \,\,\, \vec r } \right]\, = ...$