Question
Multiply the following:
$ \left(3 x^2+4 x-8\right),\left(2 x^2-4 x+3\right)$
$ \left(3 x^2+4 x-8\right),\left(2 x^2-4 x+3\right)$
✓
Answer
$ \left(3 x^2+4 x-8\right),\left(2 x^2-4 x+3\right)$
$\left(3 x^2+4 x-8\right)\left(2 x^2-4 x+3\right)$
$=3 x^2\left(2 x^2-4 x+3\right)+4 x\left(2 x^2-4 ?+3\right)-8\left(2 x^2-4 x+3\right)$
$=6 x^4-12 x^3+9 x^2 $
$ +8 x^3-16 x^2+12 x-6 x^2+32 x-24$
$=6 x^4-12 x^3+8 x^3+9 x^2-16 x^2-16 x^2+12 x+32 x-24$
$=6 x^4-4 x^3-23 x^2+44 x-24 $
$\left(3 x^2+4 x-8\right)\left(2 x^2-4 x+3\right)$
$=3 x^2\left(2 x^2-4 x+3\right)+4 x\left(2 x^2-4 ?+3\right)-8\left(2 x^2-4 x+3\right)$
$=6 x^4-12 x^3+9 x^2 $
$ +8 x^3-16 x^2+12 x-6 x^2+32 x-24$
$=6 x^4-12 x^3+8 x^3+9 x^2-16 x^2-16 x^2+12 x+32 x-24$
$=6 x^4-4 x^3-23 x^2+44 x-24 $
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